x^2-195x+9000=0

Solution for x^2-195x+9000=0 equation:

x^2-195x+9000=0

a = 1; b = -195; c = +9000;
Δ = b2-4ac
Δ = -1952-4·1·9000
Δ = 2025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2025}=45$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-195)-45}{2*1}=\frac{150}{2}
=75
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-195)+45}{2*1}=\frac{240}{2}
=120
$